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When we photograph these different patches, we might want the white reach zone IX and the black zone I, while the coloured ones should be placed in zone VIII. Note that it is only for convenience we assume them to reflect the same amount of light. Depending on colour temperature and balancing, the real figures will certainly be other.
I would say that the coloured ones with the figures you gave are more on the left site of the histogram.
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If we measure the red patch as if it were white, and assume that we place it in zone IX, which is the place where it would rightly be if it had been white, its red luminance will be higher than the red channel of the sensor can assess. Our meter, whether completely colour indifferent as most hand held meters, or tri-colour as in a camera, will not assess its correct value to fill the red channel without over-flowing. The white patch reflected 120 cd/m2, but the red one only 30 cd/m2. The meter will tell us to expose the red patch three times more than the white patch, in order to make it as bright as a white of 120 cd/m2, but as it is one single colour, with the two other absent, it will fill up the red sensels at only a third of that exposure. The red will be clipped if we expose it in hope of getting it as bright as the white patch.
I don't know how you can measure the red patch as if it were white. But I think you mean that you overexpose the red patch so that it comes in zone IX. Then you have a problem. The tolerance you have with overexposing without clipping is determined by the highest channel value. Not by the absence of 2 other colours.
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The red coloured patch reflects less light than the white one, less cd/m2, and it cannot be used for evaluating exposure unless we know how to compensate for the lack of the other two colours. We have to reduce exposure about three times in order to render it below clipping.
And this is what I think complete nonsense.