
Originally Posted by
DanK
The more I think about this, the more I think the terminology is fine, including the use of "point" and "level."
I'll stick with just the black point because it is less typing to reference only one of the pair.
The black point is the point on the x-axis of the histogram at which the level of any pixel is 0,0,0. Initially, this is at the extremes of the histogram display. If the histogram does not reach to the left edge, then there are no pixels at that value. If you move the black point indicator to the right, you are simply rescaling the histogram, mapping the displayed histogram to a new one. Suppose, for example, that the lowest value in the observed histogram is at 20,20,20. (I'll leave the three channels equal for simplicity, but of course they needn't be.) Now move the black point indicator to 20. That creates a new distribution of luminance in which the level 20,20,20 is mapped to 0,0,0, and the rest of the distribution is stretched accordingly. (The curves tool does a similar but more complex mapping, and I've always thought that the curves tool should display the new histogram on the Y axis.)
If you continue moving the black point indicator to the right, you clip. Mathematically, that is just censoring. Pixels can't have values lower than 0,0,0--no negative numbers in this case--so all of the pixels that would be lower than that are necessarily mapped to 0,0,0, and all information about their relative luminance is lost in the new distribution.
The black point doesn't refer to an individual pixel. In the start of this example, there was a black point, but no pixels mapped to it. At the end, when the distribution was censored, there were lots of pixels mapped to it.
Does this work?