I find the statement in bold a little odd. While realizing that the A/R is not 1:1, that means that an image perfectly framed in the viewfinder will come out losing 0.00504 in the raw.Originally Posted by DPR
All I did was calculate 1/sqrt(0.99) which comes to 1.00504.
Are there photographers that gauge their framing closer than that? Is it that important?
It's not like a model would lose an ear, or half the Forth Bridge go missing ...
P.S. I might have got it backwards but my point remains, I hope.